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Investigating Forces & Motion
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Investigating Forces and Motion (1998)(Granada Learning).iso
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1998-02-10
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[question1]
type:2
caption:\
Which one of the following is not an example of uniformly accelerated \
motion?<p>
correct:A swinging pendulum
wrong1:A stone falling towards the ground
wrong2:An astronaut jumping on the Moon
wrong3:A car speeding up by 5.0 m/s each second
feedback:\
The acceleration of a pendulum bob changes direction and size as it \
swings to and fro. It is the only one of the four examples that has a \
non-uniform acceleration.<p>
[question2]
type:3
caption:\
The equations of uniformly accelerated motion apply to only one of \
these four objects. Which is it?<p>
correct:3g15d
wrong1:3g15a
wrong2:3g15b
wrong3:3g15c
feedback:\
The velocity-time graph of an object with uniform acceleration is a \
straight line. The only uniformly accelerating object of the four is \
(d). This is the only object to which the equations of uniformly \
accelerated motion can be applied.<p>
[question3]
type:3
caption:\
Which one of the equations below is not an equation of uniformly \
accelerated motion?<p>
correct:3g21a
wrong1:3g21b
wrong2:3g21c
wrong3:3g21d
feedback:\
Equation (c) gives the kinetic (motion) energy of a moving mass. It is \
not one of the equations of uniformly accelerated motion.<p>
[question4]
type:1
image:3g16
caption:\
By how much does the displacement of this object increase between \
<I>t</I> = 0.0 s and <I>t </I>= 4.0 s?<p>
correct:8.0 m
wrong1:2.0 m
wrong2:6.0 m
wrong3:4.0 m
feedback:\
The increase in displacement is equal to the area under the graph \
between <I>t</I> = 0.0 s and <I>t</I> = 4.0 s.<p>\
Area = 4.0 x 2.0 = 8.0 m.<p>
[question5]
type:1
image:3g17
caption:\
What is the increase in displacement of this object between<p>\
<I>t</I> = 0.0 s and <I>t</I> = 2.0 s?<p>
correct:4.0 m
wrong1:1.0 m
wrong2:2.0 m
wrong3:3.0 m
feedback:\
The increase in displacement is equal to the area under the graph \
between <I>t</I> = 0.0 s and <I>t</I> = 2.0 s.<p>\
Area = 1/2 x 2.0 x 4.0 = 4.0 m.<p>
[question6]
type:1
image:3g18
caption:\
What is the increase in displacement of this object between<p>\
<I>t</I> = 2.0 s and <I>t</I> = 3.0 s?<p>
correct:3.0 m
wrong1:1.0 m
wrong2:2.0 m
wrong3:4.0 m
feedback:\
The increase in displacement is equal to the area under the graph \
between <I>t</I> = 2.0 s and <I>t</I> = 3.0 s.<p>\
Area = area of rectangle + area of triangle<p>\
<center>= (1.0 x 2.0) + ½ x (1.0 x 2.0) = 3.0 m.</center><p>
[question7]
type:2
caption:\
A car travelling at 10 m/s starts to accelerate in a straight line \
with an acceleration 2.0 m/s<sup>2</sup>. How fast is it travelling \
4.0 seconds later?<p>
correct:18 m/s
wrong1:2.0 m/s
wrong2:8.0 m/s
wrong3:12 m/s
feedback:\
Take the direction of travel as positive. Write down the knowns and \
unknowns in the problem.<p>\
<I>u</I> = 10 m/s<p>\
<I>a</I> = 2.0 m/s<sup>2</sup><p>\
<I>t</I> = 4.0 s<p>\
<I>v</I> = ?<p>\
Use <I>v</I> = <I>u</I> + <I>at<p>\
</I><p>\
<center>= 10 + 2.0 x 4.0</center><p>\
<center>= 18 m/s.</center><p>
[question8]
type:2
caption:\
A car travelling at 10 m/s starts to accelerate in a straight line \
with an acceleration of 2.0 m/s<sup>2</sup>. How far does it travel in \
the next 4.0 seconds?<p>
correct:56 m
wrong1:40 m
wrong2:16 m
wrong3:10 m
feedback:\
Take the direction of travel as positive. Write down the knowns and \
unknowns in the problem.<p>\
<I>u</I>= 10 m/s<p>\
<I>a</I> = 2.0 m/s<sup>2</sup><p>\
<I>t</I> = 4.0 s<p>\
<I>s</I> = ?<p>\
Use <I>s</I> = <I>ut</I> + ½<I>at</I><sup>2</sup><p>\
<center>= (10.0 x 4.0) + ½ x (2.0 x 4.0<sup>2</sup>)</center><p>\
<center>= 56 m.</center><p>
[question9]
type:2
caption:\
A cyclist travelling at 8.0 m/s brakes. If the cyclist travels a \
further 8.0 m before coming to rest what was the average \
acceleration?<p>
correct:-4.0 m/s<sup>2</sup>
wrong1:-1.0 m/s<sup>2</sup>
wrong2:-2.0 m/s<sup>2</sup>
wrong3:-8.0 m/s<sup>2</sup>
feedback:\
Take the direction of travel as positive. Write down the knowns and \
unknowns in the problem.<p>\
<I>u</I> = 8.0 m/s<p>\
<I>v</I> = 0.0 m/s<p>\
<I>s</I> = 8.0 m<p>\
<I>a</I> = ?<p>\
Use <I>v</I><sup>2</sup> = <I>u</I><sup>2</sup> + 2<I>as<p>\
</I><p>\
0.0 = 8.0<sup>2</sup> + 2<I>a</I> x 8.0<p>\
0 = 64 + 16<i>a</i><p>\
<i>a</i> = -64/16<p>\
a = -4.0 m/s<sup>2</sup>.<p>
[question10]
type:2
caption:\
A cyclist travelling at 8.0 m/s brakes but travels a further 8.0 m \
before coming to a complete rest. How long did it take for the bicycle \
to stop?<p>
correct:2.0 s
wrong1:1.0 s
wrong2:4.0 s
wrong3:8.0 s
feedback:\
Take the direction of travel as positive. Write down the knowns and \
unknowns in the problem.<p>\
<I>u</I> = 8.0 m/s<p>\
<I>v</I> = 0.0 m/s<p>\
<I>s</I> = 8.0 m<p>\
<I>t</I> = ?<p>\
Use <img src="sa3q10a" align=center><p>\
8.0 = ½ (8.0 + 0.0) <I>t<p>\
</I><p>\
16 = 8.0<I>t<p>\
</I><p>\
<I>t</I> = 2.0 s.<p>
[question11]
type:2
caption:\
A pebble is dropped from a cliff 20 m above the beach. How long is it \
before the pebble hits the sand? (Assume that the acceleration due to \
gravity is <I>g</I> = 10 m/s<sup>2</sup>.)<p>
correct:2.0 s
wrong1:1.0 s
wrong2:3.0 s
wrong3:4.0 s
feedback:\
Take 'down' as positive. Write down the knowns and unknowns in the \
problem.<p>\
<I>u</I> = 0.0 m/s<p>\
<I>s</I> = 20 m<p>\
<I>a</I> = 10 m/s<sup>2</sup><p>\
<i>t</i> = ?<p>\
Use <I>s</I> = <I>ut</I> + ½<I>at</I><sup>2</sup><p>\
20 = 0.0 + ½ x 10 x <I>t</I><sup>2</sup><p>\
<I>t</I><sup>2</sup> = 20/5<p>\
<I>t</I><sup>2</sup> = 4.0<p>\
<I>t</I> = 2.0 s.<p>
[question12]
type:2
caption:\
A pebble is dropped from a cliff 20 m above the beach. How fast is the \
pebble travelling when it hits the sand? (Assume that air resistance \
is negligible and the acceleration due to gravity, <I>g</I> = 10 \
m/s<sup>2</sup>.)<p>
correct:20 m/s
wrong1:2.0 m/s
wrong2:5.0 m/s
wrong3:10 m/s
feedback:\
Take 'down' as positive. Write down the knowns and unknowns in the \
problem.<p>\
<I>u</I> = 0.0 m/s<p>\
<I>s</I> = 20 m<p>\
<I>a</I> = 10 m/s<sup>2</sup><p>\
<i>v</i> = ?<p>\
Use <I>v</I><sup>2</sup> = <I>u</I><sup>2</sup> + 2<I>as<p>\
</I><p>\
<I>v</I><sup>2</sup> = 0.0<sup>2</sup> + 2.0 x 10 x 20<p>\
<I>v</I><sup>2</sup> = 20 x 20<p>\
<I>v</I> = 20 m/s.<p>
[question13]
type:2
caption:\
A juggler throws a ball vertically into the air and catches it at the \
same level 2.0 s later. How high did the ball rise? (Assume that air \
resistance is negligible and the acceleration due to gravity, <I>g</I> \
= 10 m/s<sup>2</sup>.)<p>
correct:5.0 m
wrong1:2.0 m
wrong2:10 m
wrong3:20 m
feedback:\
Take 'down' as positive. The ball's velocity when it reaches its \
highest point will be zero. Consider the second half of the motion \
only. The initial velocity is zero. The time to fall back from the \
highest point is half the total time of 2.0 s. Write down the knowns \
and unknowns in the problem.<p>\
<I>u</I> = 0.0 m/s<p>\
<I>t</I> = 1.0 s<p>\
<I>a</I> = 10 m/s<sup>2</sup><p>\
<I>s</I> = ?<p>\
Use <I>s</I> = <I>ut</I>+ ½<I>at</I><sup>2</sup><p>\
s = 0.0 + ½ x 10 x 1.0<sup>2</sup><p>\
s = 5.0 m.<p>
[question14]
type:2
caption:\
A juggler throws a ball vertically into the air and catches it at the \
same level 2.0 s later. How fast was the ball travelling when it left \
the juggler's hand? (Assume that air resistance is negligible the \
acceleration due to gravity, <I>g</I> = 10 m/s<sup>2</sup>.)<p>
correct:10 m/s
wrong1:2.0 m/s
wrong2:5.0 m/s
wrong3:20 m/s
feedback:\
Take 'up' as positive. Consider the first half of the motion only. The \
ball's velocity when it reaches its highest point will be zero. The \
time to reach the highest point is half the total time of 2.0 s. Write \
down the knowns and unknowns in the problem.<p>\
<I>v</I> = 0.0 m/s<p>\
<I>t</I> = 1.0 s<p>\
<I>a</I> = -10 m/s<sup>2</sup><p>\
<I>u</I> = ?<p>\
Use <I>v</I> = <I>u</I> + <I>at<p>\
</I><p>\
0.0 = <I>u</I> - 10 x 1.0<p>\
<I>u</I> = 10 m/s.<p>
[question15]
type:2
caption:\
A frog leaps vertically into the air at a speed of 2.0 m/s. How high \
does it jump? (Assume that air resistance is negligible and the \
acceleration due to gravity, <I>g</I> = 10 m/s<sup>2</sup>.)<p>
correct:0.2 m
wrong1:0.5 m
wrong2:1.0 m
wrong3:2.0 m
feedback:\
Take 'up' as positive. The frog's velocity when it reaches its highest \
point will be zero. Write down the knowns and unknowns in the \
problem.<p>\
<I>u</I> = 2.0 m/s<p>\
<I>v = </I>0.0 m/s<p>\
<I>a</I> = -10 m/s<sup>2</sup><p>\
<I>s</I> = ?<p>\
Use <I>v</I><sup>2</sup> = <I>u</I><sup>2</sup> + 2<I>as<p>\
</I><p>\
<I>0</I> = 2<sup>2</sup> - 2 x 10 x <I>s<p>\
</I><p>\
20<I> s</I> = 4.0<p>\
<I>s</I> = 4.0/20<p>\
s = 0.2 m.<p>
[question16]
type:2
caption:\
A frog leaps vertically into the air at a speed of 2.0 m/s. How long \
is it in the air? (Assume that air resistance is negligible and the \
acceleration due to gravity, <I>g</I> = 10 m/s<sup>2</sup>.)<p>
correct:0.4 s
wrong1:0.2 s
wrong2:1.0 s
wrong3:2.4 s
feedback:\
Take 'up' as positive. The frog's velocity when it reaches its highest \
point will be zero. The time to reach the highest point will be half \
the total time in the air. Write down the knowns and unknowns in the \
problem.<p>\
<I>u</I> = 2.0 m/s<p>\
<I>v</I> = 0.0 m/s<p>\
<I>a</I> = -10 m/s<sup>2</sup><p>\
<I>t</I> = ?<p>\
Use <I>v</I> = <I>u</I> + <I>at<p>\
</I><p>\
0.0 = 2 - 10<I>t<p>\
</I><p>\
10<I>t</I> = 2<p>\
<I>t</I> = 2/10<p>\
t = 0.2 s<p>\
Therefore total time = 2.0 x 0.2 = 0.4 s.<p>
[question17]
type:2
caption:\
A space craft must decelerate from a speed 10 000 m/s to 2 000 m/s as \
it approaches a moon. If the maximum acceleration that the bodies of \
the astronauts can withstand is 100 m/s<sup>2</sup> how long will the \
deceleration take?<p>
correct:80 s
wrong1:1 000 s
wrong2:800 s
wrong3:100 s
feedback:\
Take the direction of motion as positive. Write down the knowns and \
unknowns in the problem.<p>\
<I>u</I> = 10 000 m/s<p>\
<I>v</I> = 2 000 m/s<p>\
<I>a</I> = -100 m/s<sup>2</sup><p>\
<I>t</I> = ?<p>\
Use <I>v</I> = <I>u</I> + <I>at<p>\
</I><p>\
2 000 = 10 000 - 100<I>t<p>\
</I><p>\
100<I>t</I> = 8 000<p>\
<I>t</I> = 8 000/100<p>\
t = 80 s.<p>
[question18]
type:2
caption:\
A space craft must decelerate from a speed 10 000 m/s to 2 000 m/s as \
it approaches a moon. If the maximum acceleration that the bodies of \
the astronauts can withstand is 100 m/s<sup>2</sup> how far from the \
moon must the deceleration start?<p>
correct:480 km
wrong1:480 m
wrong2:4 800 m
wrong3:4 800 km
feedback:\
Take the direction of motion as positive. Write down the knowns and \
unknowns in the problem.<p>\
<I>u</I> = 10 000 m/s<p>\
<I>v</I> = 2 000 m/s<p>\
<I>a</I> = -100 m/s<sup>2</sup><p>\
<I>s</I> = ?<p>\
Use <I>v</I><sup>2</sup> = <I>u</I><sup>2</sup> + 2<I>as<p>\
</I><p>\
2 000<sup>2</sup> = 10 000<sup>2</sup> - 2 x 100<I>t<p>\
</I><p>\
200<I>t</I> = 100 000 000 - 4 000 000<p>\
<I>t</I> = 96 000 000/200<p>\
<i>t</i> = 480 000 m<p>\
<i>t</i> = 480 km.<p>
[question19]
type:1
image:3g19
caption:\
This graph shows how the velocity of an object undergoing a uniform \
acceleration changes with time. What is the object's acceleration?<p>
correct:1.0 m/s<sup>2</sup>
wrong1:2.0 m/s<sup>2</sup>
wrong2:5.0 m/s<sup>2</sup>
wrong3:10 m/s<sup>2</sup>
feedback:\
The gradient of a velocity-time graph is the acceleration.<p>\
Gradient = 1.0 m/s<sup>2</sup>.<p>
[question20]
type:1
image:3g20
caption:\
This graph shows how the velocity of an object undergoing a uniform \
acceleration changes with time. By how much does the object's \
displacement increase between t = 1.0 s and t = 3.0 s?<p>
correct:6.0 m
wrong1:1.0 m
wrong2:2.0 m
wrong3:5.0 m
feedback:\
The area under a velocity-time graph is the increase in \
displacement.<p>\
area between t = 1.0 s and t = 3.0 s is equal to the area of the \
rectangle plus the area of the triangle.<p>\
displacement = 2.0 x 2.0 + 1/2 x 2.0 x 2.0<p>\
displacement = 6.0 m.<p>